What is the integral of e^{-0.6t} ?

The integral of e^{-0.6t} is -1.66666…e^{-0.6t}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{-0.6t}

\int e^{- 0.6 t} d t

- 1.66666 \dots e^{- 0.6 t} + C

Solution steps

\int e^{- 0.6 t} d t

Apply u-substitution

: \int - \frac{1}{0.6} e^{u} d u

= \int - \frac{1}{0.6} e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{0.6} \cdot \int e^{u} d u

Simplify

= - 1.66666 \dots \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - 1.66666 \dots e^{u}

Substitute back

u = - 0.6 t

= - 1.66666 \dots e^{- 0.6 t}

Add a constant to the solution

= - 1.66666 \dots e^{- 0.6 t} + C

\int \frac{e ^{7 x}}{e ^{7 x} + 6} d x

\int (\frac{x}{16 - x ^{2}}) d x

\int \frac{3 x}{( x + 1 ) ^{3}} d x

\int t e^{t - 1} d t

\int e^{\frac{x ^{2} - 2 x}{100}} (20 x - 20) d x

What is the integral of e^{-0.6t} ?
The integral of e^{-0.6t} is -1.66666…e^{-0.6t}+C