What is the integral of (e^t+2/(t^2)) ?

The integral of (e^t+2/(t^2)) is e^t-2/t+C

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integral of (e^t+2/(t^2))

\int (e^{t} + \frac{2}{t ^{2}}) d t

e^{t} - \frac{2}{t} + C

Solution steps

\int e^{t} + \frac{2}{t ^{2}} d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{t} d t + \int \frac{2}{t ^{2}} d t

\int e^{t} d t = e^{t}

\int \frac{2}{t ^{2}} d t = - \frac{2}{t}

= e^{t} - \frac{2}{t}

Add a constant to the solution

= e^{t} - \frac{2}{t} + C

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What is the integral of (e^t+2/(t^2)) ?
The integral of (e^t+2/(t^2)) is e^t-2/t+C