What is the integral of (x+1)/(x(x+ln(x))) ?

The integral of (x+1)/(x(x+ln(x))) is ln|x+ln(x)|+C

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integral of (x+1)/(x(x+ln(x)))

\int \frac{x + 1}{x ( x + ln ( x ) )} d x

ln ∣ x + ln (x) ∣ + C

Solution steps

\int \frac{x + 1}{x ( x + ln ( x ) )} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = x + ln (x)

= ln ∣ x + ln (x) ∣

Add a constant to the solution

= ln ∣ x + ln (x) ∣ + C

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What is the integral of (x+1)/(x(x+ln(x))) ?
The integral of (x+1)/(x(x+ln(x))) is ln|x+ln(x)|+C