What is the integral of (sqrt(x)+\sqrt[3]{2}) ?

The integral of (sqrt(x)+\sqrt[3]{2}) is 2/3 x^{3/2}+\sqrt[3]{2}x+C

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integral of (sqrt(x)+\sqrt[3]{2})

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int x d x = \frac{2}{3} x^{\frac{3}{2}}

Add a constant to the solution

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\int \frac{( 1 - 2 x - x ^{2} )}{( x + 1 ) ^{2}} d x

What is the integral of (sqrt(x)+\sqrt[3]{2}) ?
The integral of (sqrt(x)+\sqrt[3]{2}) is 2/3 x^{3/2}+\sqrt[3]{2}x+C