What is the integral of 1/(7x+11) ?

The integral of 1/(7x+11) is 1/7 ln|7x+11|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(7x+11)

\int \frac{1}{7 x + 11} d x

\frac{1}{7} ln ∣ 7 x + 11 ∣ + C

Solution steps

\int \frac{1}{7 x + 11} d x

Apply u-substitution

: \int \frac{1}{7 u} d u

= \int \frac{1}{7 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{7} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{7} ln ∣ u ∣

Substitute back

u = 7 x + 11

= \frac{1}{7} ln ∣ 7 x + 11 ∣

Add a constant to the solution

= \frac{1}{7} ln ∣ 7 x + 11 ∣ + C

\int 3 x 1 - 4 x^{2} d x

\int cos (x) (sec (x) + tan (x)) d x

\int (x - 5) (3 x + 4) d x

\int (5 x^{3} + 6 x^{3} - 5) d x

What is the integral of 1/(7x+11) ?
The integral of 1/(7x+11) is 1/7 ln|7x+11|+C