What is the integral of e^{7x-7} ?

The integral of e^{7x-7} is 1/7 e^{7x-7}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of e^{7x-7}

\int e^{7 x - 7} d x

\frac{1}{7} e^{7 x - 7} + C

Solution steps

\int e^{7 x - 7} d x

Apply u-substitution

: \int e^{u} \frac{1}{7} d u

= \int e^{u} \frac{1}{7} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{7} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{7} e^{u}

Substitute back

u = 7 x - 7

= \frac{1}{7} e^{7 x - 7}

Add a constant to the solution

= \frac{1}{7} e^{7 x - 7} + C

\int \frac{ln ( 9 x )}{x ^{5}} d x

\int \frac{1}{( x ^{2} + 1 ) ( x - 1 )} d x

\int 5 e^{x} + 7 d x

\int (cos (x))^{3} \cdot sin (x) d x

\int \frac{( 2 x ^{3} - x ^{2} ) ^{2}}{3 x ^{3}} d x