What is the integral of (10)/(2x+5) ?

The integral of (10)/(2x+5) is 5ln|2x+5|+C

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integral of (10)/(2x+5)

\int \frac{10}{2 x + 5} d x

5 ln ∣ 2 x + 5 ∣ + C

Solution steps

\int \frac{10}{2 x + 5} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int \frac{1}{2 x + 5} d x

Apply u-substitution

: \int \frac{1}{2 u} d u

= 10 \cdot \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \frac{1}{2} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= 10 \cdot \frac{1}{2} ln ∣ u ∣

Substitute back

u = 2 x + 5

= 10 \cdot \frac{1}{2} ln ∣ 2 x + 5 ∣

Simplify

10 \cdot \frac{1}{2} ln ∣ 2 x + 5 ∣ : 5 ln ∣ 2 x + 5 ∣

= 5 ln ∣ 2 x + 5 ∣

Add a constant to the solution

= 5 ln ∣ 2 x + 5 ∣ + C

\int 5 e^{x} + 5 d x

\int e^{(- 4 x)} d x

\int 5 e^{x} + 3 d x

\int 1 + x^{2} \cdot x d x

What is the integral of (10)/(2x+5) ?
The integral of (10)/(2x+5) is 5ln|2x+5|+C