What is the integral of (2x+1)/(x^2-2x+2) ?

The integral of (2x+1)/(x^2-2x+2) is ln|x^2-2x+2|+3arctan(x-1)+C

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integral of (2x+1)/(x^2-2x+2)

\int \frac{2 x + 1}{x ^{2} - 2 x + 2} d x

ln x^{2} - 2 x + 2 + 3 arctan (x - 1) + C

Solution steps

\int \frac{2 x + 1}{x ^{2} - 2 x + 2} d x

Complete the square

x^{2} - 2 x + 2 : (x - 1)^{2} + 1

= \int \frac{2 x + 1}{( x - 1 ) ^{2} + 1} d x

Apply u-substitution

: \int \frac{2 u + 3}{u ^{2} + 1} d u

= \int \frac{2 u + 3}{u ^{2} + 1} d u

Expand

\frac{2 u + 3}{u ^{2} + 1} : \frac{2 u}{u ^{2} + 1} + \frac{3}{u ^{2} + 1}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2 u}{u ^{2} + 1} d u + \int \frac{3}{u ^{2} + 1} d u

\int \frac{2 u}{u ^{2} + 1} d u = ln u^{2} + 1

\int \frac{3}{u ^{2} + 1} d u = 3 arctan (u)

= ln u^{2} + 1 + 3 arctan (u)

Substitute back

u = x - 1

= ln (x - 1)^{2} + 1 + 3 arctan (x - 1)

Expand

(x - 1)^{2} + 1 : x^{2} - 2 x + 2

= ln x^{2} - 2 x + 2 + 3 arctan (x - 1)

Add a constant to the solution

= ln x^{2} - 2 x + 2 + 3 arctan (x - 1) + C

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What is the integral of (2x+1)/(x^2-2x+2) ?
The integral of (2x+1)/(x^2-2x+2) is ln|x^2-2x+2|+3arctan(x-1)+C