What is the integral of (x+sec^2(x)) ?

The integral of (x+sec^2(x)) is (x^2)/2+tan(x)+C

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integral of (x+sec^2(x))

\int (x + sec^{2} (x)) d x

\frac{x ^{2}}{2} + tan (x) + C

Solution steps

\int x + sec^{2} (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x + \int sec^{2} (x) d x

\int x d x = \frac{x ^{2}}{2}

\int sec^{2} (x) d x = tan (x)

= \frac{x ^{2}}{2} + tan (x)

Add a constant to the solution

= \frac{x ^{2}}{2} + tan (x) + C

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What is the integral of (x+sec^2(x)) ?
The integral of (x+sec^2(x)) is (x^2)/2+tan(x)+C