What is the integral of-6x^{1/2}+7 ?

The integral of-6x^{1/2}+7 is -4x^{3/2}+7x+C

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integral of-6x^{1/2}+7

\int - 6 x^{\frac{1}{2}} + 7 d x

- 4 x^{\frac{3}{2}} + 7 x + C

Solution steps

\int - 6 x^{\frac{1}{2}} + 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 6 x^{\frac{1}{2}} d x + \int 7 d x

\int 6 x^{\frac{1}{2}} d x = 4 x^{\frac{3}{2}}

\int 7 d x = 7 x

= - 4 x^{\frac{3}{2}} + 7 x

Add a constant to the solution

= - 4 x^{\frac{3}{2}} + 7 x + C

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What is the integral of-6x^{1/2}+7 ?
The integral of-6x^{1/2}+7 is -4x^{3/2}+7x+C