What is the integral of a*e^{-ax} ?

The integral of a*e^{-ax} is -e^{-ax}+C

Popular >

integral of a*e^{-ax}

\int a \cdot e^{- a x} d x

- e^{- a x} + C

Solution steps

\int a e^{- a x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= a \cdot \int e^{- a x} d x

Apply u-substitution

: \int - \frac{e ^{u}}{a} d u

= a \cdot \int - \frac{e ^{u}}{a} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= a (- \frac{1}{a} \cdot \int e^{u} d u)

Use the common integral:

\int e^{u} d u = e^{u}

= a (- \frac{1}{a} e^{u})

Substitute back

u = - a x

= a (- \frac{1}{a} e^{- a x})

Simplify

a (- \frac{1}{a} e^{- a x}) : - e^{- a x}

= - e^{- a x}

Add a constant to the solution

= - e^{- a x} + C

\int \frac{1}{( cos ^{2} ( x ) 1 + tan ( x ) )} d x

\int \frac{arctan ^{3} ( x )}{3 x ^{2} + 3} d x

\int arctan (tan (t)) d t

\int x (1 + x^{2}) d x