What is the integral of 2e^tt ?

The integral of 2e^tt is 2(e^tt-e^t)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 2e^tt

\int 2 e^{t} t d t

2 (e^{t} t - e^{t}) + C

Solution steps

\int 2 e^{t} t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int e^{t} t d t

Apply Integration By Parts

: e^{t} t - \int e^{t} d t

= 2 (e^{t} t - \int e^{t} d t)

\int e^{t} d t = e^{t}

= 2 (e^{t} t - e^{t})

Add a constant to the solution

= 2 (e^{t} t - e^{t}) + C

\int \frac{- 6 x + 18}{( x ^{2} + 2 x + 4 ) ^{2}} d x

\int - \frac{60}{x ^{2}} d x

\int \frac{x}{( x ^{2} - 9 ) ^{5}} d x

\int 3 x^{2} - 1 d x

\int (3 x - 1)^{20} d x