What is the integral of cos(5x+4n)sin^2(5x+4n) ?

The integral of cos(5x+4n)sin^2(5x+4n) is 1/15 sin^3(5x+4n)+C

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integral of cos(5x+4n)sin^2(5x+4n)

\int cos (5 x + 4 n) sin^{2} (5 x + 4 n) d x

\frac{1}{15} sin^{3} (5 x + 4 n) + C

Solution steps

\int cos (5 x + 4 n) sin^{2} (5 x + 4 n) d x

Apply u-substitution

: \int cos (u) sin^{2} (u) \frac{1}{5} d u

= \int cos (u) sin^{2} (u) \frac{1}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int cos (u) sin^{2} (u) d u

Apply u-substitution

: \int v^{2} d v

= \frac{1}{5} \cdot \int v^{2} d v

Apply the Power Rule

: \frac{v ^{3}}{3}

= \frac{1}{5} \cdot \frac{v ^{3}}{3}

Substitute back

= \frac{1}{5} \cdot \frac{sin ^{3} ( 5 x + 4 n )}{3}

Simplify

\frac{1}{5} \cdot \frac{sin ^{3} ( 5 x + 4 n )}{3} : \frac{1}{15} sin^{3} (5 x + 4 n)

= \frac{1}{15} sin^{3} (5 x + 4 n)

Add a constant to the solution

= \frac{1}{15} sin^{3} (5 x + 4 n) + C

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What is the integral of cos(5x+4n)sin^2(5x+4n) ?
The integral of cos(5x+4n)sin^2(5x+4n) is 1/15 sin^3(5x+4n)+C