What is the integral of ((sqrt(x))/3+8/(sqrt(x))) ?

The integral of ((sqrt(x))/3+8/(sqrt(x))) is 2/9 x^{3/2}+16sqrt(x)+C

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integral of ((sqrt(x))/3+8/(sqrt(x)))

\int (\frac{x}{3} + \frac{8}{x}) d x

\frac{2}{9} x^{\frac{3}{2}} + 16 x + C

Solution steps

\int \frac{x}{3} + \frac{8}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{x}{3} d x + \int \frac{8}{x} d x

\int \frac{x}{3} d x = \frac{2}{9} x^{\frac{3}{2}}

\int \frac{8}{x} d x = 16 x

= \frac{2}{9} x^{\frac{3}{2}} + 16 x

Add a constant to the solution

= \frac{2}{9} x^{\frac{3}{2}} + 16 x + C

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What is the integral of ((sqrt(x))/3+8/(sqrt(x))) ?
The integral of ((sqrt(x))/3+8/(sqrt(x))) is 2/9 x^{3/2}+16sqrt(x)+C