What is the integral of 5+2/3 x^2+3/4 x^3 ?

The integral of 5+2/3 x^2+3/4 x^3 is 5x+(2x^3)/9+(3x^4)/(16)+C

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integral of 5+2/3 x^2+3/4 x^3

\int 5 + \frac{2}{3} x^{2} + \frac{3}{4} x^{3} d x

5 x + \frac{2 x ^{3}}{9} + \frac{3 x ^{4}}{16} + C

Solution steps

\int 5 + \frac{2}{3} x^{2} + \frac{3}{4} x^{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 d x + \int \frac{2}{3} x^{2} d x + \int \frac{3}{4} x^{3} d x

\int 5 d x = 5 x

\int \frac{2}{3} x^{2} d x = \frac{2 x ^{3}}{9}

\int \frac{3}{4} x^{3} d x = \frac{3 x ^{4}}{16}

= 5 x + \frac{2 x ^{3}}{9} + \frac{3 x ^{4}}{16}

Add a constant to the solution

= 5 x + \frac{2 x ^{3}}{9} + \frac{3 x ^{4}}{16} + C

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What is the integral of 5+2/3 x^2+3/4 x^3 ?
The integral of 5+2/3 x^2+3/4 x^3 is 5x+(2x^3)/9+(3x^4)/(16)+C