What is the integral of 2e^{x/7} ?

The integral of 2e^{x/7} is 14e^{x/7}+C

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integral of 2e^{x/7}

\int 2 e^{\frac{x}{7}} d x

14 e^{\frac{x}{7}} + C

Solution steps

\int 2 e^{\frac{x}{7}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int e^{\frac{x}{7}} d x

Apply u-substitution

: \int e^{u} \cdot 7 d u

= 2 \cdot \int e^{u} \cdot 7 d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot 7 \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= 2 \cdot 7 e^{u}

Substitute back

u = \frac{x}{7}

= 2 \cdot 7 e^{\frac{x}{7}}

Simplify

= 14 e^{\frac{x}{7}}

Add a constant to the solution

= 14 e^{\frac{x}{7}} + C

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