What is the integral of 4x^3sqrt(x^4)+7 ?

The integral of 4x^3sqrt(x^4)+7 is (2x^6)/3+7x+C

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integral of 4x^3sqrt(x^4)+7

\int 4 x^{3} x^{4} + 7 d x

\frac{2 x ^{6}}{3} + 7 x + C

Solution steps

\int 4 x^{3} x^{4} + 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x^{3} x^{4} d x + \int 7 d x

\int 4 x^{3} x^{4} d x = \frac{2 x ^{6}}{3}

\int 7 d x = 7 x

= \frac{2 x ^{6}}{3} + 7 x

Add a constant to the solution

= \frac{2 x ^{6}}{3} + 7 x + C

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What is the integral of 4x^3sqrt(x^4)+7 ?
The integral of 4x^3sqrt(x^4)+7 is (2x^6)/3+7x+C