What is the integral of ((x^4)/4) ?

The integral of ((x^4)/4) is (x^5)/(20)+C

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integral of ((x^4)/4)

\int (\frac{x ^{4}}{4}) d x

\frac{x ^{5}}{20} + C

Solution steps

\int \frac{x ^{4}}{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int x^{4} d x

Apply the Power Rule

: \frac{x ^{5}}{5}

= \frac{1}{4} \cdot \frac{x ^{5}}{5}

Simplify

\frac{1}{4} \cdot \frac{x ^{5}}{5} : \frac{x ^{5}}{20}

= \frac{x ^{5}}{20}

Add a constant to the solution

= \frac{x ^{5}}{20} + C

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