What is the integral of (x^3)ln(x)(1) ?

The integral of (x^3)ln(x)(1) is 1/4 x^4ln(x)-(x^4)/(16)+C

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integral of (x^3)ln(x)(1)

\int (x^{3}) ln (x) (1) d x

\frac{1}{4} x^{4} ln (x) - \frac{x ^{4}}{16} + C

Solution steps

\int x^{3} ln (x) \cdot 1 d x

Simplify

= \int x^{3} ln (x) d x

Apply Integration By Parts

: \frac{1}{4} x^{4} ln (x) - \int \frac{x ^{3}}{4} d x

= \frac{1}{4} x^{4} ln (x) - \int \frac{x ^{3}}{4} d x

\int \frac{x ^{3}}{4} d x = \frac{x ^{4}}{16}

= \frac{1}{4} x^{4} ln (x) - \frac{x ^{4}}{16}

Add a constant to the solution

= \frac{1}{4} x^{4} ln (x) - \frac{x ^{4}}{16} + C

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What is the integral of (x^3)ln(x)(1) ?
The integral of (x^3)ln(x)(1) is 1/4 x^4ln(x)-(x^4)/(16)+C