What is the integral of sqrt(x) 1 ?

The integral of sqrt(x) 1 is d 2/3 x^{3/2}+C

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integral of sqrt(x) 1

\int x \frac{d}{1} d x

d \frac{2}{3} x^{\frac{3}{2}} + C

Solution steps

\int x \frac{d}{1} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= d \cdot \int x d x

Apply the Power Rule

: \frac{2}{3} x^{\frac{3}{2}}

= d \frac{2}{3} x^{\frac{3}{2}}

Add a constant to the solution

= d \frac{2}{3} x^{\frac{3}{2}} + C

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What is the integral of sqrt(x) 1 ?
The integral of sqrt(x) 1 is d 2/3 x^{3/2}+C