What is the derivative of f(x)=x^3-3x+4 ?

The derivative of f(x)=x^3-3x+4 is 3x^2-3

What is the first derivative of f(x)=x^3-3x+4 ?

The first derivative of f(x)=x^3-3x+4 is 3x^2-3

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derivative of

f (x) = x^{3} - 3 x + 4

3 x^{2} - 3

Solution steps

\frac{d}{d x} (x^{3} - 3 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (4)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4) = 0

= 3 x^{2} - 3 + 0

Simplify

= 3 x^{2} - 3

y^{^{''}} + 6 y^{^{'}} + 5 y = 2 x

f (x) = 3 x^{\frac{1}{2}} + x^{\frac{3}{2}}, at x = 16

\int \frac{2}{x ( ln ( x ) ) ^{2}} d x

\frac{x ^{2}}{( 2 + x )}

y^{^{''}} - 8 y^{^{'}} - 17 y = 0

What is the derivative of f(x)=x^3-3x+4 ?
The derivative of f(x)=x^3-3x+4 is 3x^2-3
What is the first derivative of f(x)=x^3-3x+4 ?
The first derivative of f(x)=x^3-3x+4 is 3x^2-3