What is the integral of e^{2x}sqrt(e^{2x)+1} ?

The integral of e^{2x}sqrt(e^{2x)+1} is 1/3 (e^{2x}+1)^{3/2}+C

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integral of e^{2x}sqrt(e^{2x)+1}

\int e^{2 x} e^{2 x} + 1 d x

\frac{1}{3} (e^{2 x} + 1)^{\frac{3}{2}} + C

Solution steps

\int e^{2 x} e^{2 x} + 1 d x

Apply u-substitution

: \int \frac{u}{2} d u

= \int \frac{u}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{1}{2} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = e^{2 x} + 1

= \frac{1}{2} \cdot \frac{2}{3} (e^{2 x} + 1)^{\frac{3}{2}}

Simplify

\frac{1}{2} \cdot \frac{2}{3} (e^{2 x} + 1)^{\frac{3}{2}} : \frac{1}{3} (e^{2 x} + 1)^{\frac{3}{2}}

= \frac{1}{3} (e^{2 x} + 1)^{\frac{3}{2}}

Add a constant to the solution

= \frac{1}{3} (e^{2 x} + 1)^{\frac{3}{2}} + C

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What is the integral of e^{2x}sqrt(e^{2x)+1} ?
The integral of e^{2x}sqrt(e^{2x)+1} is 1/3 (e^{2x}+1)^{3/2}+C