What is the integral of e^{x+x^2} ?

The integral of e^{x+x^2} is \sqrt[4]{e}(sqrt(pi))/2 \erfi(x+1/2)+C

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integral of e^{x+x^2}

\int e^{x + x^{2}} d x

Solution steps

\int e^{x + x^{2}} d x

Complete the square

x + x^{2} : (x + \frac{1}{2})^{2} - \frac{1}{4}

= \int e^{(x + \frac{1}{2})^{2} - \frac{1}{4}} d x

Apply u-substitution

: \int e^{u^{2} - \frac{1}{4}} d u

= \int e^{u^{2} - \frac{1}{4}} d u

Simplify

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Use the nonelementary integral:

\int e^{u^{2}} d u = \frac{π}{2} erfi (u)

Substitute back

u = x + \frac{1}{2}

Add a constant to the solution

\int (2 x + 1)^{- \frac{1}{3}} d x

\int \frac{( x - 1 )}{x ^{3} + x ^{2} - 4 x - 4} d x

\int i n^{5} x d x

\int \frac{- 3 ln ( x )}{x} d x

\int \frac{t}{3} d t

What is the integral of e^{x+x^2} ?
The integral of e^{x+x^2} is \sqrt[4]{e}(sqrt(pi))/2 \erfi(x+1/2)+C