What is the integral of 1/(m^2+1) ?

The integral of 1/(m^2+1) is arctan(m)+C

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integral of 1/(m^2+1)

\int \frac{1}{m ^{2} + 1} d m

arctan (m) + C

Solution steps

\int \frac{1}{m ^{2} + 1} d m

Use the common integral:

\int \frac{1}{m ^{2} + 1} d m = arctan (m)

= arctan (m)

Add a constant to the solution

= arctan (m) + C

\int 1 - \frac{1}{x ^{2} + 1} d x

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