What is the integral of 6x^{sqrt(3)+3} ?

The integral of 6x^{sqrt(3)+3} is 6*(4-sqrt(3))/(13)x^{4+sqrt(3)}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 6x^{sqrt(3)+3}

\int 6 x^{3 + 3} d x

6 \cdot \frac{4 - 3}{13} x^{4 + 3} + C

Solution steps

\int 6 x^{3 + 3} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int x^{3 + 3} d x

Apply the Power Rule

: \frac{4 - 3}{13} x^{4 + 3}

= 6 \cdot \frac{4 - 3}{13} x^{4 + 3}

Add a constant to the solution

= 6 \cdot \frac{4 - 3}{13} x^{4 + 3} + C

\int \frac{x - 8}{x ( x ^{2} - 4 x + 4 )} d x

\int csch^{2} (θ) e^{c o t h (θ)} d θ

\int \frac{1}{1 + ( x - 5 ) ^{2}} d x

\int \frac{x}{( 1 + x ) ^{\frac{3}{4}}} d x

\int 8 x^{4} - 6 x^{3} + 4 x^{2} + C d x

What is the integral of 6x^{sqrt(3)+3} ?
The integral of 6x^{sqrt(3)+3} is 6*(4-sqrt(3))/(13)x^{4+sqrt(3)}+C