What is the integral of 1/(11x-6) ?

The integral of 1/(11x-6) is 1/11 ln|11x-6|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 1/(11x-6)

\int \frac{1}{11 x - 6} d x

\frac{1}{11} ln ∣ 11 x - 6 ∣ + C

Solution steps

\int \frac{1}{11 x - 6} d x

Apply u-substitution

: \int \frac{1}{11 u} d u

= \int \frac{1}{11 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{11} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{11} ln ∣ u ∣

Substitute back

u = 11 x - 6

= \frac{1}{11} ln ∣ 11 x - 6 ∣

Add a constant to the solution

= \frac{1}{11} ln ∣ 11 x - 6 ∣ + C

\int x^{9} ln (7 x^{5}) d x

\int (6 - x) e^{\frac{x}{3}} d x

\int 21 csc (3 x) cot (3 x) d x

\int (x^{3} + x^{2})^{15} (3 x^{2} + 2 x) d x

\int (5 x^{4} + 3 x^{2} + 6) d x

What is the integral of 1/(11x-6) ?
The integral of 1/(11x-6) is 1/11 ln|11x-6|+C