What is the integral of-x^2+8x-12 ?

The integral of-x^2+8x-12 is -(x^3)/3+4x^2-12x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of-x^2+8x-12

\int - x^{2} + 8 x - 12 d x

- \frac{x ^{3}}{3} + 4 x^{2} - 12 x + C

Solution steps

\int - x^{2} + 8 x - 12 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int x^{2} d x + \int 8 x d x - \int 12 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 8 x d x = 4 x^{2}

\int 12 d x = 12 x

= - \frac{x ^{3}}{3} + 4 x^{2} - 12 x

Add a constant to the solution

= - \frac{x ^{3}}{3} + 4 x^{2} - 12 x + C

\int x^{3} (x^{4} + 2) d x

\int d tan (x) d x

\int \frac{x + 3}{x ^{3} - x ^{2} + x - 1} d x

\int \frac{x ^{2}}{- x ^{2} + 4 x - 4} d x

\int \frac{3}{1 + x + 1} d x

What is the integral of-x^2+8x-12 ?
The integral of-x^2+8x-12 is -(x^3)/3+4x^2-12x+C