What is the integral of (-sin(2x))/(cos(2x)) ?

The integral of (-sin(2x))/(cos(2x)) is 1/2 ln|cos(2x)|+C

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integral of (-sin(2x))/(cos(2x))

\int \frac{- sin ( 2 x )}{cos ( 2 x )} d x

\frac{1}{2} ln ∣ cos (2 x) ∣ + C

Solution steps

\int \frac{- sin ( 2 x )}{cos ( 2 x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{sin ( 2 x )}{cos ( 2 x )} d x

Apply u-substitution

: \int - \frac{1}{2 u} d u

= - \int - \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \frac{1}{2} \cdot \int \frac{1}{u} d u)

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - (- \frac{1}{2} ln ∣ u ∣)

Substitute back

u = cos (2 x)

= - (- \frac{1}{2} ln ∣ cos (2 x) ∣)

Simplify

= \frac{1}{2} ln ∣ cos (2 x) ∣

Add a constant to the solution

= \frac{1}{2} ln ∣ cos (2 x) ∣ + C

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What is the integral of (-sin(2x))/(cos(2x)) ?
The integral of (-sin(2x))/(cos(2x)) is 1/2 ln|cos(2x)|+C