What is the integral from 1 to infinity of 1/(x^2) ?

The integral from 1 to infinity of 1/(x^2) is 1

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integral from 1 to infinity of 1/(x^2)

\int_{1}^{\infty} \frac{1}{x ^{2}} d x

1

Solution steps

\int_{1}^{\infty} \frac{1}{x ^{2}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{2}} d x = - \frac{1}{x} + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{x ^{2}} d x = 0 - (- 1)

= 0 - (- 1)

Simplify

= 1

ln (x + 1), 2

\frac{\partial}{\partial x} (\frac{x ^{2}}{( y - x ) ^{2}})

n = 1 \sum \infty \frac{2}{n ^{8}}

\int 8 x^{4} d x

\int x sin^{2} (x^{\frac{3}{2}} - 1) d x

What is the integral from 1 to infinity of 1/(x^2) ?
The integral from 1 to infinity of 1/(x^2) is 1