What is the integral of-1/(cos^2(y)) ?

The integral of-1/(cos^2(y)) is -tan(y)+C

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integral of-1/(cos^2(y))

\int - \frac{1}{cos ^{2} ( y )} d y

- tan (y) + C

Solution steps

\int - \frac{1}{cos ^{2} ( y )} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int \frac{1}{cos ^{2} ( y )} d y

Use the common integral:

\int \frac{1}{cos ^{2} ( y )} d y = tan (y)

= - tan (y)

Add a constant to the solution

= - tan (y) + C

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What is the integral of-1/(cos^2(y)) ?
The integral of-1/(cos^2(y)) is -tan(y)+C