What is the integral of (3sin(y)) ?

The integral of (3sin(y)) is -3cos(y)+C

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integral of (3sin(y))

\int (3 sin (y)) d y

- 3 cos (y) + C

Solution steps

\int 3 sin (y) d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int sin (y) d y

Use the common integral:

\int sin (y) d y = - cos (y)

= 3 (- cos (y))

Simplify

= - 3 cos (y)

Add a constant to the solution

= - 3 cos (y) + C

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