What is the integral of x^9sqrt(x) ?

The integral of x^9sqrt(x) is 2/21 x^{21/2}+C

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integral of x^9sqrt(x)

\int x^{9} x d x

\frac{2}{21} x^{\frac{21}{2}} + C

Solution steps

\int x^{9} x d x

Simplify

x^{9} x : x^{\frac{19}{2}}

= \int x^{\frac{19}{2}} d x

Apply the Power Rule

: \frac{2}{21} x^{\frac{21}{2}}

= \frac{2}{21} x^{\frac{21}{2}}

Add a constant to the solution

= \frac{2}{21} x^{\frac{21}{2}} + C

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What is the integral of x^9sqrt(x) ?
The integral of x^9sqrt(x) is 2/21 x^{21/2}+C