What is the integral of (2019+sec(x)tan(x)-e^x) ?

The integral of (2019+sec(x)tan(x)-e^x) is 2019x+sec(x)-e^x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (2019+sec(x)tan(x)-e^x)

\int (2019 + sec (x) tan (x) - e^{x}) d x

2019 x + sec (x) - e^{x} + C

Solution steps

\int 2019 + sec (x) tan (x) - e^{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2019 d x + \int sec (x) tan (x) d x - \int e^{x} d x

\int 2019 d x = 2019 x

\int sec (x) tan (x) d x = sec (x)

\int e^{x} d x = e^{x}

= 2019 x + sec (x) - e^{x}

Add a constant to the solution

= 2019 x + sec (x) - e^{x} + C

\int 0.5 e^{- 0.4 x} d x

\int x e^{x z} d z

\int 45 x \cdot e^{3 x} d x

\int \frac{3}{4} e^{2 x} d x

\int - \frac{1}{5 t 25 t ^{2} - 25} d t

What is the integral of (2019+sec(x)tan(x)-e^x) ?
The integral of (2019+sec(x)tan(x)-e^x) is 2019x+sec(x)-e^x+C