What is the integral of 4sqrt(x)+8 ?

The integral of 4sqrt(x)+8 is 8/3 x^{3/2}+8x+C

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integral of 4sqrt(x)+8

\int 4 x + 8 d x

\frac{8}{3} x^{\frac{3}{2}} + 8 x + C

Solution steps

\int 4 x + 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x d x + \int 8 d x

\int 4 x d x = \frac{8}{3} x^{\frac{3}{2}}

\int 8 d x = 8 x

= \frac{8}{3} x^{\frac{3}{2}} + 8 x

Add a constant to the solution

= \frac{8}{3} x^{\frac{3}{2}} + 8 x + C

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What is the integral of 4sqrt(x)+8 ?
The integral of 4sqrt(x)+8 is 8/3 x^{3/2}+8x+C