What is the integral of sqrt(x^2(a^2-x^2)) ?

The integral of sqrt(x^2(a^2-x^2)) is -1/3 (a^2-x^2)^{3/2}+C

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integral of sqrt(x^2(a^2-x^2))

\int x^{2} (a^{2} - x^{2}) d x

- \frac{1}{3} (a^{2} - x^{2})^{\frac{3}{2}} + C

Solution steps

\int x^{2} (a^{2} - x^{2}) d x

Simplify

x^{2} (a^{2} - x^{2}) : x a^{2} - x^{2}

= \int x a^{2} - x^{2} d x

Apply u-substitution

: \int - \frac{u}{2} d u

= \int - \frac{u}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= - \frac{1}{2} \cdot \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = a^{2} - x^{2}

= - \frac{1}{2} \cdot \frac{2}{3} (a^{2} - x^{2})^{\frac{3}{2}}

Simplify

- \frac{1}{2} \cdot \frac{2}{3} (a^{2} - x^{2})^{\frac{3}{2}} : - \frac{1}{3} (a^{2} - x^{2})^{\frac{3}{2}}

= - \frac{1}{3} (a^{2} - x^{2})^{\frac{3}{2}}

Add a constant to the solution

= - \frac{1}{3} (a^{2} - x^{2})^{\frac{3}{2}} + C

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What is the integral of sqrt(x^2(a^2-x^2)) ?
The integral of sqrt(x^2(a^2-x^2)) is -1/3 (a^2-x^2)^{3/2}+C