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Popular >

integral of 1/(7+x)

Solution

\int \frac{1}{7 + x} d x

Solution

ln ∣ 7 + x ∣ + C

Solution steps

\int \frac{1}{7 + x} d x

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = 7 + x

= ln ∣ 7 + x ∣

Add a constant to the solution

= ln ∣ 7 + x ∣ + C

Popular Examples

integral of 1/(4sqrt(u))

\int \frac{1}{4 u} d u

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\int \frac{e ^{2 t}}{e ^{2 t} + 3} d t

integral of 1/(35+12x-36x^2)

\int \frac{1}{35 + 12 x - 36 x ^{2}} d x

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\int 14 e^{u} d u

integral of 1/(4^2+9)

\int \frac{1}{4 ^{2} + 9} d x

Frequently Asked Questions (FAQ)

What is the integral of 1/(7+x) ?
The integral of 1/(7+x) is ln|7+x|+C