What is the integral of sqrt(x)+e^{-2x} ?

The integral of sqrt(x)+e^{-2x} is 2/3 x^{3/2}-1/2 e^{-2x}+C

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integral of sqrt(x)+e^{-2x}

\int x + e^{- 2 x} d x

\frac{2}{3} x^{\frac{3}{2}} - \frac{1}{2} e^{- 2 x} + C

Solution steps

\int x + e^{- 2 x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x + \int e^{- 2 x} d x

\int x d x = \frac{2}{3} x^{\frac{3}{2}}

\int e^{- 2 x} d x = - \frac{1}{2} e^{- 2 x}

= \frac{2}{3} x^{\frac{3}{2}} - \frac{1}{2} e^{- 2 x}

Add a constant to the solution

= \frac{2}{3} x^{\frac{3}{2}} - \frac{1}{2} e^{- 2 x} + C

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What is the integral of sqrt(x)+e^{-2x} ?
The integral of sqrt(x)+e^{-2x} is 2/3 x^{3/2}-1/2 e^{-2x}+C