What is the integral of 1/(3sqrt(t)) ?

The integral of 1/(3sqrt(t)) is 2/3 sqrt(t)+C

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integral of 1/(3sqrt(t))

\int \frac{1}{3 t} d t

\frac{2}{3} t + C

Solution steps

\int \frac{1}{3 t} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int \frac{1}{t} d t

Apply the Power Rule

: 2 t^{\frac{1}{2}}

= \frac{1}{3} \cdot 2 t^{\frac{1}{2}}

Simplify

\frac{1}{3} \cdot 2 t^{\frac{1}{2}} : \frac{2}{3} t

= \frac{2}{3} t

Add a constant to the solution

= \frac{2}{3} t + C

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What is the integral of 1/(3sqrt(t)) ?
The integral of 1/(3sqrt(t)) is 2/3 sqrt(t)+C