What is the integral of (9r^3)/(r^2) ?

The integral of (9r^3)/(r^2) is (9r^2)/2+C

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integral of (9r^3)/(r^2)

\int \frac{9 r ^{3}}{r ^{2}} d r

\frac{9 r ^{2}}{2} + C

Solution steps

\int \frac{9 r ^{3}}{r ^{2}} d r

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int \frac{r ^{3}}{r ^{2}} d r

Simplify

\frac{r ^{3}}{r ^{2}} : r

= 9 \cdot \int r d r

Apply the Power Rule

: \frac{r ^{2}}{2}

= 9 \cdot \frac{r ^{2}}{2}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{9 r ^{2}}{2}

Add a constant to the solution

= \frac{9 r ^{2}}{2} + C

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What is the integral of (9r^3)/(r^2) ?
The integral of (9r^3)/(r^2) is (9r^2)/2+C