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Popular >

integral of 1/(y+9)

Solution

\int \frac{1}{y + 9} d y

Solution

ln ∣ y + 9 ∣ + C

Solution steps

\int \frac{1}{y + 9} d y

Apply u-substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = y + 9

= ln ∣ y + 9 ∣

Add a constant to the solution

= ln ∣ y + 9 ∣ + C

Graph

Popular Examples

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\int - 4 x sin (x + 2) d x

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\int 1.2 x 1 + 3 x^{2} d x

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\int \frac{2 x - 1}{x ^{2} + 3 x - 10} d x

integral of 1/x 1/(1+x^2)

\int \frac{1}{x} \frac{1}{1 + x ^{2}} d x

integral of (4x)/3+y^2

\int \frac{4 x}{3} + y^{2} d y

Frequently Asked Questions (FAQ)

What is the integral of 1/(y+9) ?
The integral of 1/(y+9) is ln|y+9|+C