What is the integral of 0.16e^{-0.16x} ?

The integral of 0.16e^{-0.16x} is -e^{-0.16x}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 0.16e^{-0.16x}

\int 0.16 e^{- 0.16 x} d x

- e^{- 0.16 x} + C

Solution steps

\int 0.16 e^{- 0.16 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.16 \cdot \int e^{- 0.16 x} d x

Apply u-substitution

: \int - \frac{1}{0.16} e^{u} d u

= 0.16 \cdot \int - \frac{1}{0.16} e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 0.16 (- \frac{1}{0.16} \cdot \int e^{u} d u)

Simplify

= 0.16 (- 6.25 \cdot \int e^{u} d u)

Use the common integral:

\int e^{u} d u = e^{u}

= 0.16 (- 6.25 e^{u})

Substitute back

u = - 0.16 x

= 0.16 (- 6.25 e^{- 0.16 x})

Simplify

= - e^{- 0.16 x}

Add a constant to the solution

= - e^{- 0.16 x} + C

\int 5 x 1^{2} + 5^{2} d x

\int x^{2} \cdot 2 x^{3} + 1 d x

\int (e^{x} + ln (y) + \frac{y}{x}) d x

\int (x^{3} - x)^{2} d x

\int \frac{2 - x}{1 + 4 x - x ^{2}} d x

What is the integral of 0.16e^{-0.16x} ?
The integral of 0.16e^{-0.16x} is -e^{-0.16x}+C