What is the integral of x^4+\sqrt[3]{x}-5 ?

The integral of x^4+\sqrt[3]{x}-5 is (x^5)/5+3/4 x^{4/3}-5x+C

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integral of x^4+\sqrt[3]{x}-5

\frac{x ^{5}}{5} + \frac{3}{4} x^{\frac{4}{3}} - 5 x + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int x^{4} d x = \frac{x ^{5}}{5}

\int 5 d x = 5 x

= \frac{x ^{5}}{5} + \frac{3}{4} x^{\frac{4}{3}} - 5 x

Add a constant to the solution

= \frac{x ^{5}}{5} + \frac{3}{4} x^{\frac{4}{3}} - 5 x + C

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What is the integral of x^4+\sqrt[3]{x}-5 ?
The integral of x^4+\sqrt[3]{x}-5 is (x^5)/5+3/4 x^{4/3}-5x+C