What is the integral of (10x+10)/(x(x-1)) ?

The integral of (10x+10)/(x(x-1)) is 20ln|x-1|-10ln|x|+C

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integral of (10x+10)/(x(x-1))

\int \frac{10 x + 10}{x ( x - 1 )} d x

20 ln ∣ x - 1 ∣ - 10 ln ∣ x ∣ + C

Solution steps

\int \frac{10 x + 10}{x ( x - 1 )} d x

Expand

\frac{10 x + 10}{x ( x - 1 )} : \frac{10 x}{x ( x - 1 )} + \frac{10}{x ( x - 1 )}

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{10 x}{x ( x - 1 )} d x + \int \frac{10}{x ( x - 1 )} d x

\int \frac{10 x}{x ( x - 1 )} d x = 10 ln ∣ x - 1 ∣

\int \frac{10}{x ( x - 1 )} d x = 10 (- ln ∣ x ∣ + ln ∣ x - 1 ∣)

= 10 ln ∣ x - 1 ∣ + 10 (- ln ∣ x ∣ + ln ∣ x - 1 ∣)

Simplify

10 ln ∣ x - 1 ∣ + 10 (- ln ∣ x ∣ + ln ∣ x - 1 ∣) : 20 ln ∣ x - 1 ∣ - 10 ln ∣ x ∣

= 20 ln ∣ x - 1 ∣ - 10 ln ∣ x ∣

Add a constant to the solution

= 20 ln ∣ x - 1 ∣ - 10 ln ∣ x ∣ + C

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What is the integral of (10x+10)/(x(x-1)) ?
The integral of (10x+10)/(x(x-1)) is 20ln|x-1|-10ln|x|+C