What is the integral of sqrt(x^3+2x)(3x^2+2) ?

The integral of sqrt(x^3+2x)(3x^2+2) is 2/3 (x^3+2x)^{3/2}+C

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integral of sqrt(x^3+2x)(3x^2+2)

\int x^{3} + 2 x (3 x^{2} + 2) d x

\frac{2}{3} (x^{3} + 2 x)^{\frac{3}{2}} + C

Solution steps

\int x^{3} + 2 x (3 x^{2} + 2) d x

Apply u-substitution

: \int u d u

= \int u d u

Apply the Power Rule

: \frac{2}{3} u^{\frac{3}{2}}

= \frac{2}{3} u^{\frac{3}{2}}

Substitute back

u = x^{3} + 2 x

= \frac{2}{3} (x^{3} + 2 x)^{\frac{3}{2}}

Add a constant to the solution

= \frac{2}{3} (x^{3} + 2 x)^{\frac{3}{2}} + C

\int - 3 x^{2} + 2 x d x

\int \frac{x ^{2} + 1}{x ^{6}} d x

\int \frac{1}{- 3 x ^{2}} d x

\int (5 y) d y

tan^{4} (x)

What is the integral of sqrt(x^3+2x)(3x^2+2) ?
The integral of sqrt(x^3+2x)(3x^2+2) is 2/3 (x^3+2x)^{3/2}+C