What is the integral of (x^3)/(12) ?

The integral of (x^3)/(12) is (x^4)/(48)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (x^3)/(12)

\int \frac{x ^{3}}{12} d x

\frac{x ^{4}}{48} + C

Solution steps

\int \frac{x ^{3}}{12} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{12} \cdot \int x^{3} d x

Apply the Power Rule

: \frac{x ^{4}}{4}

= \frac{1}{12} \cdot \frac{x ^{4}}{4}

Simplify

\frac{1}{12} \cdot \frac{x ^{4}}{4} : \frac{x ^{4}}{48}

= \frac{x ^{4}}{48}

Add a constant to the solution

= \frac{x ^{4}}{48} + C

\int \frac{( 3 + 2 x )}{4 e ^{4 x}} d x

\int \frac{( x + 1 )}{4 x ^{2} - 4 x + 1} d x

\int 15 x cos (\frac{1}{2}) x d x

\int sec^{2} (x) (1 - 4 x) d x

\int x \cdot e^{x^{2} - 1} d x