What is the integral of 1/(1+x^2)1+x^2) ?

The integral of 1/(1+x^2)1+x^2) is dx+C

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integral of 1/(1+x^2)1+x^2)

\int \frac{1}{1 + x ^{2}} d (1 + x^{2}) d x

d x + C

Solution steps

\int \frac{1}{1 + x ^{2}} d (1 + x^{2}) d x

Simplify

\frac{1}{1 + x ^{2}} d (1 + x^{2}) : d

= \int dd x

Integral of a constant:

\int a d x = a x

= d x

Add a constant to the solution

= d x + C

\int e^{- x^{3}} (- 3 x^{2}) d x

\int 20 e^{- 20 (x - 12.5)} d x

\int \frac{1}{3 t ^{3}} d t

\int \frac{x ^{5}}{1 - 9 x ^{12}} d x

\int \frac{x ^{- 1}}{( ln ( x ) ) ^{2}} d x

What is the integral of 1/(1+x^2)1+x^2) ?
The integral of 1/(1+x^2)1+x^2) is dx+C