What is the integral of-2x^4+3x^2-1 ?

The integral of-2x^4+3x^2-1 is -(2x^5)/5+x^3-x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of-2x^4+3x^2-1

\int - 2 x^{4} + 3 x^{2} - 1 d x

- \frac{2 x ^{5}}{5} + x^{3} - x + C

Solution steps

\int - 2 x^{4} + 3 x^{2} - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 2 x^{4} d x + \int 3 x^{2} d x - \int 1 d x

\int 2 x^{4} d x = \frac{2 x ^{5}}{5}

\int 3 x^{2} d x = x^{3}

\int 1 d x = x

= - \frac{2 x ^{5}}{5} + x^{3} - x

Add a constant to the solution

= - \frac{2 x ^{5}}{5} + x^{3} - x + C

\int \frac{1}{( x ^{2} - x + 1 ) ^{2}} d x

\int \frac{sin ( t )}{1 + sin ( t )} d t

\int cos (3 x + π) d x

\int sin^{7} (\frac{x}{3}) cos (\frac{x}{3}) d x

\int - 8 e^{- 0.1 t} d t

What is the integral of-2x^4+3x^2-1 ?
The integral of-2x^4+3x^2-1 is -(2x^5)/5+x^3-x+C