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Popular >

integral of 2Re(z)

Solution

\int 2 R e (z) d z

Solution

e R z^{2} + C

Solution steps

\int 2 R ez d z

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 R e \cdot \int z d z

Apply the Power Rule

: \frac{z ^{2}}{2}

= 2 R e \frac{z ^{2}}{2}

Simplify

2 R e \frac{z ^{2}}{2} : e R z^{2}

= e R z^{2}

Add a constant to the solution

= e R z^{2} + C

Popular Examples

integral of (x^2-1)/(x^2-4)+a

\int \frac{x ^{2} - 1}{x ^{2} - 4} + a d x

integral of x/((1+xy)^2)

\int \frac{x}{( 1 + x y ) ^{2}} d y

integral of x^2(4-2x+x^3)

\int x^{2} (4 - 2 x + x^{3}) d x

integral of 1/(sqrt(x^2-2ax))

\int \frac{1}{x ^{2} - 2 a x} d x

integral of (2x^4)/(x^2+1)

\int \frac{2 x ^{4}}{x ^{2} + 1} d x

Frequently Asked Questions (FAQ)

What is the integral of 2Re(z) ?
The integral of 2Re(z) is eRz^2+C