What is the integral of cot(10pi)x+sin(2x) ?

The integral of cot(10pi)x+sin(2x) is Undefined-1/2 cos(2x)+C

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integral of cot(10pi)x+sin(2x)

\int cot (10 π) x + sin (2 x) d x

Undefined - \frac{1}{2} cos (2 x) + C

Solution steps

\int cot (10 π) x + sin (2 x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int cot (10 π) x d x + \int sin (2 x) d x

\int cot (10 π) x d x =

Undefined

\int sin (2 x) d x = - \frac{1}{2} cos (2 x)

= Undefined - \frac{1}{2} cos (2 x)

Add a constant to the solution

= Undefined - \frac{1}{2} cos (2 x) + C

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What is the integral of cot(10pi)x+sin(2x) ?
The integral of cot(10pi)x+sin(2x) is Undefined-1/2 cos(2x)+C