What is the integral of 8sqrt(t) ?

The integral of 8sqrt(t) is 16/3 t^{3/2}+C

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integral of 8sqrt(t)

\int 8 t d t

\frac{16}{3} t^{\frac{3}{2}} + C

Solution steps

\int 8 t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int t d t

Apply the Power Rule

: \frac{2}{3} t^{\frac{3}{2}}

= 8 \cdot \frac{2}{3} t^{\frac{3}{2}}

Simplify

8 \cdot \frac{2}{3} t^{\frac{3}{2}} : \frac{16}{3} t^{\frac{3}{2}}

= \frac{16}{3} t^{\frac{3}{2}}

Add a constant to the solution

= \frac{16}{3} t^{\frac{3}{2}} + C

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